# Difference between revisions of "String Sort List"

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The sort operation uses the merge-sort algorithm, which takes time O(n log n) where n is the length of the list. | The sort operation uses the merge-sort algorithm, which takes time O(n log n) where n is the length of the list. | ||

− | [[Category:CookBook]] | + | [[Category:CookBook]][[Category:ListRecipes]] |

## Revision as of 23:16, 3 September 2006

Sorting a list of strings

## Problem

You want to sort a list of strings.

## Solution

Use the lists:sort operation to sort the lists. Note that by default sorting is case-sensitive. However, since you can use the lists:sort/2 variant of the function to supply your own sorting function this can be modified.

1> lists:sort(["foo", "bar", "baz", "qux"]). ["bar","baz","foo","qux"] 2> lists:sort(fun(A, B) -> A =< B end, ["foo", "bar", "baz", "qux"]). ["bar","baz","foo","qux"] 3> lists:sort(fun(A, B) -> A =< B end, ["foo", "bar", "baz", "qux"]). ["bar","baz","foo","qux"] 4> lists:sort(fun(A, B) -> A >= B end, ["foo", "bar", "baz", "qux"]). ["qux","foo","baz","bar"]

The sort operation uses the merge-sort algorithm, which takes time O(n log n) where n is the length of the list.