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Difference between revisions of "Floating Point Compare"

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(remove irritating angsting, remove bogus reference to 'imaginary' Erlang bignums and its consequent reasoning (hint: Erlang has bignums.))
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== Solution ==
 
== Solution ==
  
Erlang (unforunately) does not implement the full tower of numerics, which would provide built-in support for access to exact and inexact integers, bignum support, and a raft of other tools making this particular recipe somewhat unnecessary.
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Implement a "fuzzy match" on two real numbers where the difference is below some epsilon threshhold.  
 
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Consequently, we will implement a "fuzzy match" on two real numbers where the difference is below some epsilon threshhold.  
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In these cases, you can use floating-point byte strings to represent and compare numbers:  
 
In these cases, you can use floating-point byte strings to represent and compare numbers:  
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true
 
true
 
</code>
 
</code>
 
It would obviously be better to make use of some (imaginary) Erlang bignum and exact integer facility to carry calculations through your programs with the highest level of precision. However, Erlang does not consistently provide the level of detail necessary for certain mathematical operations. Consequently, it is frequently useful to provide "fuzzy" matching on numerical terms. Hopefully this recipe can help deal with those situations.
 
  
 
A final thought:  
 
A final thought:  

Revision as of 15:22, 24 September 2006

Problem

You want to compare two floating-point numbers and know if they are equal. Unfortunately, floating-point arithmetic is not precise so very few results will match exactly. Consequently, we usually want to compare floating point values up to a certain number of decimal places.

Solution

Implement a "fuzzy match" on two real numbers where the difference is below some epsilon threshhold.

In these cases, you can use floating-point byte strings to represent and compare numbers:

1> Aval = 8.001e-3 * 9.001e5.
7201.70
2> Bval = 8.0011e-3 * 9.001e5.
7201.79
3> Aval == Bval.
false
4> ABin = << Aval/float >>.
<<64,188,33,179,57,192,235,237>>
5> BBin = << Bval/float >>.
<<64,188,33,202,68,166,34,63>>
6> << ABinTest:3/binary, ARest:5/binary >> = ABin.
<<64,188,33,179,57,192,235,237>>
7> ABinTest.
<<64,188,33>>
8> << BBinTest:3/binary, BRest:5/binary >> = BBin.
<<64,188,33,202,68,166,34,63>>
9> BBinTest.
<<64,188,33>>
10> BinTest == BinTest2.
true
11> << ABinTest2:4/binary, ARest2:4/binary >> = ABin.
<<64,188,33,179,57,192,235,237>>
12> << BBinTest2:4/binary, BRest2:4/binary >> = BBin. 
<<64,188,33,202,68,166,34,63>>
13> ABinTest2 == BBinTest2.
false

Another option is to convert the numbers into strings and then compare the portions of the numbers of interest:

14> [Nsa]=io_lib:format("~.12f", [Aval]).
["7201.700099999999"]
15> [NSB]=io_lib:format("~.12f", [Bval]).  
["7201.790110000001"]
16> string:substr(NSAa, 1, 6) == string:substr(NSB, 1, 6).
true

A final thought:

20> Equal_to_digit = fun(Digit, Numa, Numb) ->                     
20> [N_a] = io_lib:format("~.12f", [Numa]),                   
20> [N_b] = io_lib:format("~.12f", [Numb]),   
20> string:substr(N_a, 1, Digit) == string:substr(N_b,1,Digit) end.
#Fun<erl_eval.18.83214871>
21> Equal_to_digit(6, Aval, Bval).
true

Note: Some error handling would obviously be necessary to handle cases where the digits are insufficient for the match.

See Also

Volume 2, Section 4.2.2 of The Art of Computer Programming